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1000x^2+24x-24=0
a = 1000; b = 24; c = -24;
Δ = b2-4ac
Δ = 242-4·1000·(-24)
Δ = 96576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{96576}=\sqrt{64*1509}=\sqrt{64}*\sqrt{1509}=8\sqrt{1509}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-8\sqrt{1509}}{2*1000}=\frac{-24-8\sqrt{1509}}{2000} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+8\sqrt{1509}}{2*1000}=\frac{-24+8\sqrt{1509}}{2000} $
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